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Prove that area of rhombus is …

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Prove that area of rhombus is equal to half of product of its diagonals

Posted by Khushi Narad 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let ABCD be a rhombus whose diagonals are AC and BD.

Then, Area of rhombus ABCD
= Area of {tex}\bigtriangleup{/tex}ABD + Area of {tex}\bigtriangleup{/tex}CBD
{tex}={(BD)(AO)\over2}+{(BD)(OC)\over2}{/tex} . .[Diagonals of a rhombus are perpendiculars to each other]
{tex}={(BD)\over2}(AO+OC)={(BD)(AC)\over2}{/tex}
={tex}1\over2{/tex} product of the lengths of its diagonals.

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CBSE > Class 10 > Mathematics