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The 4th term of an AP …

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The 4th term of an AP is zero.prove that its 25th term is triple its 11th term.
  • 2 answers

Pragya . 7 years, 4 months ago

4th term is 0. i.e., a+3d=0 therefore a=-3d 25th term is a+24d putting the value of a in 25th term = -3d+24d = 21d and, 11th term is a+10d putting the value of a in 11th term = -3d+10d = 7d 21d=3(7d) 25th term = 3 of 11th term hence proved.....

Shashank Mishra 7 years, 4 months ago

a+3d=0 a= -3d a25=a+24d=3(a11=a+10d) Put a=-3d -3d+24d=3(-3d+10d) 21d=3(7d) 21d=21d
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