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If the squared difference of the zeroes of quadriatic polynomial xsquare +px +45 is equal to144 find the value of p

Posted by Suvidhi Nahar 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Harleen Narula 7 years, 4 months ago

I'm not sure about this answer x2 +px +45 = 144 x2 +px +45 - 144 x2+ px- 99 b-4ac (px)2 - 4*x2*(-99) + 396x2 p2x2 = -396 x2 p2 = -396 x2 / x2 p2 = root - 396 . If my answer is correct so plz tell me Thank you.

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CBSE > Class 10 > Mathematics