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cosA-sinA+1/cosA+sinA-1=cosecA-cotA

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cosA-sinA+1/cosA+sinA-1=cosecA-cotA

Posted by Sandeep G 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sakshi Rawat 7 years, 4 months ago

LHS DIVIDE NUMERATOR AND DENOMINATOR BOTH BY sin A =(CosA÷sinA - sinA÷sinA +1÷sinA)/(cosA÷sinA + sinA÷sinA - 1÷sinA) =(CotA-1+cosecA)/(cotA+1-cosecA) At the place of 1 at the numerator write (cosec2A -cot2A) ={CotA+cosecA-(cosec2A-cot2A)}/(cotA-cosecA+1) ={CotA+cosecA-(cosecA+cotA)(cosecA-cotA)}/(cotA-cosecA+1) =(CotA+cosecA){1-(cosecA-cotA)}/(cotA-cosecA+1) ={(cotA+cosecA)(1-cosecA+cotA)}/(cotA-cosecA+1) =CotA+cosecA HENCE PROVED LHS=RHS

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CBSE > Class 10 > Mathematics