11term of the AP -3,-1/2, 2 …

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Sia ? 6 years, 5 months ago
The given AP is {tex} - 3,\frac{1}{2},2,......{/tex}
Here, a = -3
{tex}d = - \frac{1}{2} - ( - 3) = - \frac{1}{2} + 3 = \frac{5}{2}{/tex}
and n = 11
a11 = ?
We have, an = a + (n - 1)d
So, {tex}{a_{11}} = - 3 + (11 - 1)\left( {\frac{5}{2}} \right){/tex}
{tex} \Rightarrow {a_{11}} = - 3 + 25{/tex}
{tex} \Rightarrow {a_{11}} = 22{/tex}
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