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Prove that √2 is an irrational …

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Prove that √2 is an irrational no
  • 2 answers

Akshay Choudhary 7 years, 4 months ago

Let assume root 2 is rational Root 2=a/b(where a and b are co -prime and b is not equal to 0) Root2b=a--(1) Squaring on both sides (Root 2b)^2=a^2--(2) 2 divide a^2} 2 divide a} a=2c(where c is some integer) Put a in (2) (Root 2b)^2=(2c)^2 2b^2=4c^2 b^2=4c^2/2 b^2=2c^2 So a and b have atleast 2 as common factor. But this condradictss that a and b have no,common factor other than 1 and this aris due to incorrect assumption that root 2 is rational. Therefore root 2 is irrational. Hence proved

Ashish Sarkate 7 years, 4 months ago

Let is assume that root 2 is rational. Let a and b is a positive integer. Root 2= a/b So root 2 is rational number But this contradicts the fact that root 2 is rational But this contradiction our assumption is wrong so root 2 is rational number.
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