Obtain all the zeros of x^4+6x^3+x^2-24x-30 …

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Sia ? 6 years, 6 months ago
As x = 2 and -5 are the zeroes of x4 + 6x3 + x2- 24x - 20.

{tex}\Rightarrow{/tex} (x - 2) and (x + 5) are two factors of x4 + 6x3 + x2 -24x - 20
{tex}\Rightarrow{/tex} product of factors is (x - 2) (x + 5) = x2 + 3x - 10
Dividing x{tex}^4{/tex} + 6{tex}x^3{/tex}+ {tex}x^2{/tex} - 24x - 20 by {tex}x^2{/tex} + 3x - 10
Dividend = divisor {tex}\times{/tex} quotient + remainder
{tex}\Rightarrow{/tex} x4 + 6x3 + x2 - 24x - 20 = (x2 + 3x -10) (x2 + 3x + 2)
= (x - 2) (x + 5) (x + 2) (x + 1)
Hence, other two zeroes are -2 and -1.
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