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Sia ? 6 years, 5 months ago
The given series is:
9,15,21,27,....
a1 = 9 ,a2 = 15,a3 = 21
Here a2-a1=15-9=6
and a3-a2= 21-15=6
We found that {tex}{\mathrm a}_3-{\mathrm a}_2={\mathrm a}_2-{\mathrm a}_1=6{/tex}
Therefore the given series is an AP where a=9 and d=6
The term next to 27 = 27+ d
=27 + 6
= 33
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