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K(k-12)x²+2(k-12)x+2=0

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K(k-12)x²+2(k-12)x+2=0

Posted by Partheepan Partheepan 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

{tex}D = [2(k -12)]^2 - 4(k - 12)\times 2{/tex}
= 4(k -12)² - 8(k - 12)
For equal and real roots, D = 0
{tex}\Rightarrow{/tex}{tex}4(k - 12)^2 - 8(k - 12) = 0{/tex}
{tex}\Rightarrow{/tex}{tex}4(k - 12) (k - 12 - 2) = 0{/tex}
{tex}\Rightarrow{/tex}{tex}4(k - 12) (k - 14) = 0{/tex}
{tex}\Rightarrow{/tex}k =12 or k = 14
{tex}\because{/tex}a {tex}\ne{/tex} 0 {tex}\Rightarrow{/tex} k {tex}\ne{/tex}12; {tex}\therefore{/tex} k = 14.

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Posted by Hari Anand 6 months, 1 week ago

CBSE > Class 10 > Mathematics