If the point P(x,y) is equidistant …

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Sia ? 6 years, 6 months ago
PA = PB (Given)
{tex}\therefore {/tex} PA2 = PB2
{tex} \Rightarrow {/tex} (5 - x)2 + (1 - y)2 = (1 - x)2 + (5 - y)2
{tex} \Rightarrow {/tex} 25 + x2 - 10x + 1 + y2 - 2y = 1 + x2 - 2x + 25 + y2 - 10y
{tex} \Rightarrow {/tex} -8x = -10y + 2y
{tex} \Rightarrow {/tex} -8x = -8y
{tex} \Rightarrow {/tex} x = y
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