A vertical stick 12 m long …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Kanika . 1 month ago
- 1 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 0 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Hari Anand 6 months, 1 week ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 6 months ago
Let AB be the vertical stick and AC be its shadow. Also, let DE be the vertical tower and DF be its shadow. Join BC and EF. Let DE = x metres.
We have,
AB = 12 m, AC = 8m, and DF = 40m.
In {tex}\Delta{/tex} ABC and {tex}\Delta{/tex}DEF, we have,
{tex}\angle{/tex}A = {tex}\angle{/tex}D = 90° and {tex}\angle{/tex}C = {tex}\angle{/tex}F [Angular elevation of the sun]
Therefore, by AA- criterion of similarity, we obtain {tex}\Delta A B C \sim \Delta D E F{/tex}
{tex}\Rightarrow \quad \frac { A B } { D E } = \frac { A C } { D F }{/tex}
{tex}\Rightarrow \quad \frac { 12 } { x } = \frac { 8 } { 40 } \Rightarrow \frac { 12 } { x } = \frac { 1 } { 5 } \Rightarrow x {/tex} = 60 metres
0Thank You