A two digit no. Is such …

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Sia ? 6 years, 6 months ago
Assume digit at ten’s place = x and digit at unit’s place = y
Therefore number = 10x + y
Also xy = 15 {tex}\Rightarrow{/tex} x = {tex}\frac{15}{y}{/tex} ...(i)
According to given situation we have,
10x + y + 18 = 10y + x
{tex}\Rightarrow{/tex}9x - 9y + 18 = 0
{tex}\Rightarrow{/tex}x - y + 2 = 0
{tex}\Rightarrow{/tex}{tex}\frac{15}{y}{/tex} - y + 2 = 0 (From (i))
{tex}\Rightarrow{/tex}15 - y2 + 2y = 0
{tex}\Rightarrow{/tex}y2 - 2y - 15 = 0
On factorizing the above quadratic equation we get
(y - 5) (y + 3) = 0
{tex}\Rightarrow{/tex}y = 5, y = -3 [ y = -3 is rejected]
Put the value of y = 5 in equation (i), we obtain
x = {tex}\frac{15}{5}{/tex} = 3
{tex}\therefore{/tex} Number = 3 {tex}\times{/tex} 10 + 5 = 35.
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