A train travels a distance of …
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Sia ? 6 years, 6 months ago
Distance travelled by the train = 480 km
Let the speed of the train be x kmph
Time taken for the journey = {tex}\frac { 480 } { x }{/tex}
Given speed is decreased by 8 kmph
Hence the new speed of train = (x – 8) kmph
Time taken for the journey = {tex}\frac { 480 } { x - 8 }{/tex}
{tex}\frac { 480 } { x - 8 } = \frac { 480 } { x } + 3{/tex}
{tex}\Rightarrow{/tex} {tex}\frac { 480 } { x - 8 } - \frac { 480 } { x } = 3{/tex}
{tex}\Rightarrow \frac { 480 ( x - x + 8 ) } { x ( x - 8 ) } = 3{/tex}
{tex}\Rightarrow \frac { 480 \times 8 } { x ( x - 8 ) } = 3{/tex}
{tex}\Rightarrow 3 x ( x - 8 ) = 480 \times 8{/tex}
{tex}\Rightarrow x(x - 8 ) = 160\times 8 \\ \Rightarrow x^2 - 8x - 1280 = 0{/tex}
On solving we get x = 40
Thus the speed of train is 40 kmph.
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