Ramkali would need 1800 for admission …

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Sia ? 6 years, 6 months ago
Since, the difference between the savings of two consecutive months is Rs. 20, therefore the series is an A.P.
Here, the savings of the first month is Rs. 50
First term, a = 50, Common difference, d = 20
No. of terms = no. of months
No. of terms, n = 12
{tex}S _ { n } = \frac { n } { 2 } [ 2 a + ( n - 1 ) d ]{/tex}
{tex}= \frac { 12 } { 2 } [ 2 \times 50 + ( 12 - 1 ) 20 ]{/tex}
= 6[100 + 220]
= 6(320)
= 1920
After a year, Ramakali will save Rs. 1920.
Yes, Ramakali will be able to fulfill her dream of sending her daughter to school.
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