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ABCD is a quadrilateral in which AB parallel CD and AD parallel BC . prove that angles ADC =angels ABC

Posted by Dev Raj 7 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Suryansh Singh 7 years, 5 months ago

Here,AB//CD and BC is transversal.Then, angle BCD is equal to 180-ABC.(co -int angle) Again,angle ADC+angleBCD=180(co-int.) Angle ACD+180-ABC=180 ACD-ABC=180-180 aACD=aABC Proved

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