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ABCD is a trapezium with AB …

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ABCD is a trapezium with AB parallel to DC. A line parallel to AC interest AB at x BC At y. Prove that ar(ADX) =ar(ACY)

    • Posted by Dipasha Dev 8 years, 9 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Shweta Gulati 8 years, 9 months ago

    We know that two triangles on the same base and between the same parallels are equal in area.

     

    Consider the following figure.

     

    In the above figure, triangle ADX and ACX are on the same base AX and between the parallels AB and DC.

     

    Therefore, ar .,..(1)

    Similarly, triangle ACX and ACY are on the same base AC and between the parallels XY and AC.

     

    Therefore,  ....(2)

    From equations (1) and (2), we have

     

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