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3x+4y=10 and 2x-2y=2 solve by elimination …

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3x+4y=10 and 2x-2y=2 solve by elimination method

    • Posted by Milan Jain 6 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Alpna Suthar 6 years, 11 months ago

    Step 1: Multiply eq. 1 by 2 and eq. 2 by 3 {to equalise coefficient of x} 6x+8y=20 (eq. 3) 6x-6y= 6. ( eq.4) Step 2: Subtract eq.4 from eq. 3 6x+8y=20 6x-6y=6 -. +. - -------------------- 14y = 14 y=1 Step 3:Find x by substitution method x= 6+6y/6. =. 1 + y. =. 1+1 x =2

    0Thank You

    Shrishti Arora 6 years, 11 months ago

    3x+4y=10 (i)

    2x-2y=2 (ii)

    Multiply eqn (i) by 2 and eqn (ii) by 3 

    We get,

    6x+8y=20 - (iii)

    6x-6y=6 - (iv)

    Now solving eqn(iii) and (iv) we get 14y = 14 i.e y=1

    Substituting y=1 in eqn  (i) we get 3x=6 i. e. x=2 

    0Thank You

    ANSWER
    http://mycbseguide.com/examin8/

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