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3x+4y=10 and 2x-2y=2 solve by elimination …

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3x+4y=10 and 2x-2y=2 solve by elimination method

Posted by Milan Jain 7 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Alpna Suthar 7 years, 5 months ago

Step 1: Multiply eq. 1 by 2 and eq. 2 by 3 {to equalise coefficient of x} 6x+8y=20 (eq. 3) 6x-6y= 6. ( eq.4) Step 2: Subtract eq.4 from eq. 3 6x+8y=20 6x-6y=6 -. +. - -------------------- 14y = 14 y=1 Step 3:Find x by substitution method x= 6+6y/6. =. 1 + y. =. 1+1 x =2

0Thank You

Shrishti Arora 7 years, 5 months ago

3x+4y=10 (i)

2x-2y=2 (ii)

Multiply eqn (i) by 2 and eqn (ii) by 3

We get,

6x+8y=20 - (iii)

6x-6y=6 - (iv)

Now solving eqn(iii) and (iv) we get 14y = 14 i.e y=1

Substituting y=1 in eqn (i) we get 3x=6 i. e. x=2

0Thank You

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