Show that x=bc/ad is a solution …

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Sia ? 6 years, 5 months ago
We have, {tex}ad^2x ({a \over b}x + {2c \over d}) + c^2b =0{/tex}
{tex}\implies {a^2d^2 \over b}x^2 + 2acdx + c^2b = 0{/tex}
{tex}\implies {a^2d^2 \over b}x^2 + acdx +acdx + c^2b = 0{/tex}
{tex}\implies adx({ad \over b}x+c) + bc({ad \over b}x + c) = 0{/tex}
{tex}\implies (adx+ bc) ({ad \over b}x + c) = 0{/tex}
Either adx + bc =0 or {tex}({ad \over b}x + c) = 0{/tex}
{tex}\implies x = -{bc \over ad}{/tex}
Hence, {tex}x = -{bc \over ad}{/tex} is the requirreed solution.
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