tanx+tan2x+tanxtan2x=1
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Posted by Kabita Devi 8 years, 3 months ago
- 2 answers
Swapnal Swami 6 years, 3 months ago
tanx+tan2x = 1 - tanxtan2x
(tanx+tan2x)/(1 - tanxtan2x) = 1
tan3x = 1
3x = π/4 + nπ, n = 0, ±1, ±2, ...
x = π/12 + nπ/3
= π/12(1 + 4n)
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Ashutosh Bajpayee 4 years, 11 months ago
1Thank You