If x=2 & y=3are roots of …

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Sia ? 6 years, 6 months ago
It is given that x = 2 and x = 3 are roots of the equation 3x2 - 2kx + 2m = 0.
{tex}\therefore{/tex} 3 {tex}\times{/tex} 22 - 2k {tex}\times{/tex} 2 + 2m = 0 and 3 {tex}\times{/tex} 32 - 2k {tex}\times{/tex} 3 + 2m = 0
{tex}\Rightarrow{/tex} 12 - 4k + 2m = 0 and 27 - 6k + 2m = 0
{tex}\Rightarrow{/tex} 12 = 4k - 2m...(i) and 27 = 6k - 2m...(ii)
Solving i and ii equation, we get k = {tex}\frac { 15 } { 2 }{/tex} and m = 9
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