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In the roots of quadratic equation of 6x2-6-2=0

Posted by Nitish Patil 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

6x²- x - 2 = 0
or, 6x² + 3x - 4x - 2 = 0
or, 3x(2x + 1) -2(2x + 1) = 0
or, (2x + 1)(3x - 2) = 0
{tex}\Rightarrow{/tex} either 3x - 2 = 0 or 2x + 1 = 0
{tex}\therefore \quad x = \frac { 2 } { 3 } \text { or } x = - \frac { 1 } { 2 }{/tex}
Therefore, Roots of equation are {tex}\frac { 2 } { 3 } \text { and } - \frac { 1 } { 2 }{/tex}.

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