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If a ray OC stands on …

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If a ray OC stands on line AB such that ∆ AOC =∆COB show that ∆AOC =90°

Posted by Mohit Rana 7 years, 5 months ago

Prabjeet Singh 7 years, 5 months ago

Here, AB is a straight line and ray OC stands on line AB, such that {tex}\Delta AOC \cong \Delta COB.{/tex}

By c.p.c.t, {tex}\angle AOC=\angle COB{/tex}

Now, {tex}\angle AOC+\angle COB=180^{\circ} (\because \text {linear pair}){/tex}

{tex}\Rightarrow \angle AOC + \angle AOC = 180^{\circ}{/tex}

{tex}\Rightarrow 2\angle AOC=180^{\circ}{/tex}

{tex}\Rightarrow\angle AOC = \cfrac{180^{\circ}}{2}{/tex}

{tex}\Rightarrow \angle AOC = 90^ {\circ}{/tex}

Proved

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