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If x+y+z=0 then prove that x^3+y^3+z^3 …

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If x+y+z=0 then prove that x^3+y^3+z^3 = 3xyz

Posted by Aquibe Jawed 7 years, 5 months ago

CBSE > Class 09 > Mathematics

2 answers

Vikash Kumar 7 years, 5 months ago

x+y=-z ....equ.1 (x+y)³=(-z)³ (Cube of both sides) X³+y³+3xy(x+y)=-z³ x³+y³+3xy(-z)=-z³ (Using equ.1) x³+y³-3xyz =-z³ x³+y³+z³ =3xyz Hence, it is proved.

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Prince Anand 5 years, 8 months ago

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sides of a triangle are in the ratio of 12:17:25 and its perimeter is 540cm. find its area

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CBSE > Class 09 > Mathematics