Which term of the A.P. :21,18,15..............is …

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Sia ? 6 years, 6 months ago
The given AP is
21,18,15......................,0
Here a=21 and d=18-21= -3 and an=0,n=?
{tex}\Rightarrow{/tex} an = a + (n - 1)d
{tex}\Rightarrow{/tex} 0 = a + (n - 1)d
Now on substitution of value of a and d we get
0 = 21 + (n - 1) (-3)
-21 =(n-1)(-3)
n - 1 = {tex}\frac{{ - 21}}{{ - 3}}{/tex}
n - 1 = 7
Hence n = 8.
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