if the sum of p term …

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Sia ? 6 years, 6 months ago
Sp = Sq
{tex} \Rightarrow \frac{p}{2}\left[ {2a + (p - 1)d} \right] = \frac{q}{2}\left[ {2a + (q - 1)d} \right]{/tex}
{tex} \Rightarrow p\left[ {2a + pd - d} \right] = q\left[ {2a + qd - d} \right]{/tex}
{tex} \Rightarrow {/tex} 2ap + p2d - pd = 2aq + q2d - qd
{tex} \Rightarrow {/tex} 2a (p - q) + (p2 - q2)d - (p - q)d = 0
{tex} \Rightarrow {/tex} 2a (p - q) + (p + q) (p - q)d - (p - q)d = 0
{tex} \Rightarrow {/tex} (p - q) [2a + (p + q - 1)d] = 0
{tex} \Rightarrow {/tex} Sp+q = 0
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