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The time period of oscillation of …

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The time period of oscillation of a simple pendulum is recorded as 2.56s, 2.62s, 2.70s, 2.58s, 2.45s.find time period, absolute error in each observation and percentage error

    • Posted by Manpreet Kaur 7 years, 6 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Manpreet Kaur 7 years, 6 months ago

    Thanks for your kind help

    1Thank You

    Himanshu Jha 7 years, 6 months ago

    A1=2.56 A2=2.62 A3=2.70 A4=2.58 A5=2.45 avg a=2.582 delta a=absolute error in the measurements are=(2.56-2.58)=-0.02 (2.62-2.62)=0 (2.70-2.62)=0.08 (2.58-2.62)=-0.04 (2.45-2.62)=-0.17 mean absolute errors=(-0.02+0+0.08-0.04-0.17)/5=-0.03 relative error=±0.03/2.58=±0.011 percentage error=1.16%

    3Thank You

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