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a particle moves a distance x …

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a particle moves a distance x in time t according to equation x=(t+5)^-1 . the acceleration of particle in proportional to

    • Posted by Nancy Rajput 7 years, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Aman Kumar 7 years, 6 months ago

    X= (t+5)^-1.... V= dx/dt = -1(t+5)^-1-1..... =>V = -(t+5)^-2 ... a= d^2x/dt^2= 2(t+5)^-3... => a= -2(v)^3/2.. => a directly proportional to v^3/2

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