End term of A.p:17,14,11..-40

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Sia ? 6 years, 6 months ago
A.P. is 17,14,11,..., - 40
We have,
l = Last term = -40 , a = 17 and, d = Common difference= 14 - 17 = - 3
{tex}\therefore{/tex} 6th term from the end = l - (n -1)d
= l - (6-1) d
= -40 - 5 {tex}\times{/tex} (-3 )
= -40 + 15
= -25
So, 6th term of given A.P. is -25.
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