No products in the cart.

(3k+1)x^2 + 2(k+1)x +1 find value …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

(3k+1)x^2 + 2(k+1)x +1 find value of k which has equal roots also find roots
  • 1 answers

Sia ? 6 years, 6 months ago

The given equation is:
(3k + 1)x2 + 2(k + 1)x + 1 = 0
This is of  the form ax2 + bx + c = 0, where
a = 3k + 1, b = 2(k + 1) = 2k + 2 and c = 1
As it is given that the given equation has real and equal roots, i.e., D =  b2 - 4ac = 0. 
{tex}\Rightarrow{/tex} (2k + 2)2 - 4(3k + 1) (1) = 0
{tex}\Rightarrow{/tex} 4k+ 8k + 4 - 12k - 4 = 0
{tex}\Rightarrow{/tex} 4k- 4k = 0

{tex}\Rightarrow{/tex} 4k(k - 1) = 0
 Therefore, either  4k = 0 or k - 1 = 0
{tex}\Rightarrow{/tex} k = 0 or k = 1
Hence, the roots of given equation are  1 and 0.

https://examin8.com Test

Related Questions

X-y=5
  • 1 answers
sin60° cos 30°+ cos60° sin 30°
  • 2 answers
Venu Gopal has twice
  • 0 answers
Prove that root 8 is an irration number
  • 2 answers
(A + B )²
  • 1 answers
Find the nature of quadratic equation x^2 +x -5 =0
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App