Find the sum of all 11terms …
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Sia ? 6 years, 6 months ago
Let a be the first term and d be the common difference of the given A.P.
Clearly, in an A.P. consisting of 11 terms, {tex} \left( \frac { 11 + 1 } { 2 } \right) ^ { t h }{/tex} i.e. 6th term is the middle term.
{tex}\text{ it is given that the middle term =30}{/tex}
So a+5d=30 .....(1)
.{tex}S_{11}=\frac{11}{2}(2a+10d){/tex}
= 11(a+5d)
But a+5d=30 from (1)
Hence S11 = 11 × 30= 330
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