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How to find the value of …

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How to find the value of ( f silient not. )

    • Posted by Suraj Kumar 7 years, 2 months ago

    CBSE > Class 12 > Physics
    • 4 answers

    Saloni S 7 years, 2 months ago

    coulomb forcF=q1q2/4pie€ r^2 €=q1q2 /F 4pier^2 r^2=1st F=9×10^9th q1=q2 =1.6×10^-19th after putting the values €=8.85×10^-12C^2/Nm^2

    0Thank You

    Suraj Kumar 7 years, 2 months ago

    When put the value of ( f silient not ) is equal to 1 by 4πk how to come 9×10 to the power 9

    0Thank You

    Anamika Rajput 7 years, 2 months ago

    U may go to pradeep kshetraphal channel...best physics teacher ever.

    1Thank You

    Anamika Rajput 7 years, 2 months ago

    K = 1/4π£0 ; £0= 1/4πK = 1/4×3.14×9×10to the power 9 =8.85×10 to the power -12

    1Thank You

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