If alpha and beta are zeroes …
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Sia ? 6 years, 6 months ago
Since {tex}\alpha \text { and } \beta{/tex} are the zeroes of the polynomial, then
{tex}{/tex}{tex}\alpha + \beta = - \frac { \text { Coefficient of } x } { \text { Coefficient of } x ^ { 2 } }{/tex}{tex}{/tex}
{tex}{/tex}{tex}\Rightarrow\ \alpha + \beta = - \left( \frac { - 1 } { 1 } \right) = 1{/tex}.........(i)
Given, {tex}\alpha - \beta = 9{/tex}...............(ii)
Solving (i) and (ii), {tex}\alpha = 5 , \beta = - 4{/tex}
{tex}\alpha \beta = \frac { \text { Constant term } } { \text { Coefficient of } x ^ { 2 } }{/tex}
{tex}\Rightarrow\ \alpha \beta = - m{/tex}
{tex}\Rightarrow\ {/tex}(5)(-4) = -m
{tex}\Rightarrow{/tex}m = 20
So,required value of m is 20
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