If a polynomial x•4-3x•3-6x•2+kx-16 is exactly …

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Sia ? 6 years, 6 months ago
Given p(x) = x4 - 3x3 - 6x2 + kx - 16
and g(x) = x2 - 3x + 2
On long division of f(x) by g(x) we get

Now, remainder = (k - 24)x
When p(x) is exactly divisible by g(x), then remainder = 0
{tex}\Rightarrow{/tex} (k - 24)x = 0
k - 24 = 0
k = 24
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