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Sia ? 6 years, 6 months ago
{tex}6 ^ { n } = ( 2 \times 3 ) ^ { n } = 2 ^ { n } \times 3 ^ { n }{/tex}
{tex}\therefore \quad 5 \text { is not a factor of } 6 ^ { n }{/tex}
{tex}\therefore {/tex} It never ends with 0.
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