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A point of application of force …

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A point of application of force vector F =5î-3j^+2k^ is moved from vector r1=2î+7j^+2k^ to vector r2=-5î +2j^+3k^.Find the work done.

    • Posted by Kavya Agrawal 7 years, 6 months ago

    CBSE > Class 11 > Physics
    • 0 answers
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