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Solution of a quadratic eqn by …

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Solution of a quadratic eqn by completing the square. How to find it

Posted by Isha Gupta 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

We have, 2x² + x + 4 = 0
Dividing both sides by 2, we get

{tex}x^2 +{1 \over 2}x + 2 = 0 {/tex}

{tex}\implies (x)^2 + {1 \over 2}x + {1 \over 16} = -2 + {1 \over 16}{/tex}

{tex}\implies (x)^2 + 2(x) ({1 \over 4})+ ({1 \over4})^2= {- 32 +1 \over 16}{/tex}

{tex}\implies (x + {1 \over4})^2 = -{31 \over 16} <0{/tex}
Which is not possible, as square cannot be negative.
So, there is no real value of x which satisfy the given equation.
Therefore, the given equation has no real roots.

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CBSE > Class 10 > Mathematics