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a five years ago a woman's …

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a five years ago a woman's age was square of her son's age. find age of son five years ago present age of woman
  • 1 answers

Sia ? 6 years, 6 months ago

Suppose, the present age of father be x years and the present age of son be y years.
According to the question,
Five years hence,
Father's age = {tex}(x + 5) years{/tex}
Using the given information, we have
{tex}x + 5=3(y + 5){/tex}

{tex}\Rightarrow{/tex} {tex}x - 3y - 10=0{/tex} ...........(i)
Five years ago,

Father's age = {tex}(x - 5)years{/tex}
Son's age ={tex}(y - 5)years{/tex}
Using the given information, we get
{tex}(x - 5) = 7 (y - 5){/tex}

{tex}\Rightarrow{/tex} {tex}x - 7y + 30 = 0{/tex} ............(ii)
Subtracting equation (ii) from equation (i), we get
{tex}4y - 40 = 0{/tex}

{tex}\Rightarrow{/tex} {tex}y = 10{/tex}
Putting y = 10 in equation (i), we get
{tex}x - 30 - 10 = 0{/tex}

{tex}\Rightarrow{/tex} {tex}x = 40{/tex}
Hence, present age of father is 40 years and present age of son is 10 years.

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