Solve this equation 3x^2+2√5x-5 by quadratic …

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Susai Raj 7 years, 6 months ago
Here a=3, b = 2√5 and c=-5
x= {-b+or-√(b^2-4ac)}/2a
={-2√5+or-√(20-4×3×(-5)}/6
={-2√5 +or-√80}/6
={-2√5 +or- 4√5}/6
x=(-2√5+4√5)/6
or (-2√5-4√5)/6
x =2√5/6 or x= -6√5/6
x=√5/3 or x = -√5
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