If a,b,c are in A.P. Prove …

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Sia ? 6 years, 6 months ago
b + c, c + a, a + b will be in AP, if
(c + a) - (b + c) = (a + b) - (c + a)
{tex}\Rightarrow{/tex} a - b = b - c {tex}\Rightarrow{/tex} 2b = a + c
i.e., a, b, c are in AP.
Thus, a, b, c are in AP implies b + c, c + a, a + b are also in AP.
Hence proved.
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