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Prove that tanA +sinA ÷ tanA-sinA …

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Prove that tanA +sinA ÷ tanA-sinA = secA+ 1÷secA-1

Posted by Amit Jangra 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Susai Raj 7 years, 6 months ago

(tanA+sinA)/(tanA-sinA)
={(sinA/cosA) + sinA} / {(sinA/cosA) -sinA}
=sinA{(1/cosA) + 1} / sinA{(1/cosA)- sinA}
=(1/cosA + 1)/1/cosA - 1)
=(secA+1)/(secA-1).

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CBSE > Class 10 > Mathematics