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✓2x2+7x+5√2=0

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✓2x2+7x+5√2=0

Posted by Diwakar Sharma 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

We have, {tex}\sqrt2x^2 +7x +5\sqrt2 =0{/tex}

{tex}\implies \sqrt2x^2 +2x +5x+5\sqrt2 =0{/tex}

{tex}\implies \sqrt2x (x +\sqrt2) + 5 (x + \sqrt2) = 0{/tex}

{tex}\implies (\sqrt2x+5) (x+\sqrt2) =0{/tex}

{tex}Either\, \sqrt2x+5 =0\, or \,x+\sqrt2 =0{/tex}

{tex}\implies x = {-5 \over \sqrt2},\, -\sqrt2{/tex}

{tex}\therefore x = {-5 \over \sqrt2},\, -\sqrt2{/tex} are the required roots.

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CBSE > Class 10 > Mathematics