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Find the smallest number which leves …

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Find the smallest number which leves reminder 8and12 when division by 28 and 32 respectively?
  • 1 answers

Avinash Kumar 7 years, 6 months ago

First, we find L.C.M of 28 and 32 28= 2 . 2 . 7 32= 2 . 2 . 2 . 2 . 2 L. C. M (28,32)= 2 . 2 . 2 . 2 . 2 . 7=224 The smallest number that leaves remainder 8 and 12 when divided by 28 and 32 = 224 -(8+12) = 204 Thus, 204 is required smallest number.
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