Find the zeros of the polynomial …

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Sia ? 6 years, 6 months ago
We have,
{tex}f(x) = x^2 + x - p(p + 1){/tex}
{tex}= x^2 + (p + 1)x - px - p(p + 1) {/tex}[As x =(p + 1)x - px ]
{tex}= x[ x + (p + 1)] - p[ x + (p + 1)]{/tex}
{tex}= ( x - p)[x + (p + 1)]{/tex}
{tex}{/tex} Now, f(x) = 0
{tex}\Rightarrow{/tex} ( x - p)[x + (p + 1)] = 0
{tex}\Rightarrow{/tex} x - p = 0 or x + (p +1) = 0
{tex}\Rightarrow{/tex} x = p or x = -(p + 1)
Thus, the required zeros of f(x) are p and -(p + 1).
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