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Sin48.sec42+cos48.cosec42=o prove that

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Sin48.sec42+cos48.cosec42=o prove that
  • 1 answers

Vishal Pratap Singh Vishal 7 years, 6 months ago

Sin48 = cos42 Using sinA = cos (90-A) Cos48 = sin42 Using cosA= sin(90-A) Now back to question cos42.sec42 + sine42.cosec42 Cos42.cos42+sine42.sine42 ANS= 1
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