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E° cu2+|cu = 0.34v ,ph =14 …

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E° cu2+|cu = 0.34v ,ph =14 , ksp of cu(oh)2 = 10 to the power -19 calcute e cell

    • Posted by Manjil Parashar 7 years, 6 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Pulkit Chandra 7 years, 6 months ago

    Ecell=E°cell-0.0891÷n log[anode]÷[cathode] n= no. of electron used during reaction E°cell=E°cathode-E°anode

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