3x2-4√3x+4=0 find roots

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Sia ? 6 years, 6 months ago
The given quadratic equation is
{tex}3 x ^ { 2 } - 4 \sqrt { 3 } x + 4 = 0{/tex}
Here, a = 3, {tex}b = - 4 \sqrt { 3 }{/tex}, c = 4
{tex}\therefore{/tex} discriminant = b2 - 4ac
{tex}= ( - 4 \sqrt { 3 } ) ^ { 2 } - 4 ( 3 ) ( 4 ){/tex}
= 48 - 48 = 0
Hence, the given quadratic equation
has two equal real roots.
The roots are {tex}= - \frac { b } { 2 a } , - \frac { b } { 2 a }{/tex}
{tex}\text { i.e. } - \frac { ( - 4 \sqrt { 3 } ) } { 2 \times 3 } , - \frac { ( - 4 \sqrt { 3 } ) } { 2 \times 3 } , \text { i.e. } \frac { 2 } { \sqrt { 3 } } , \frac { 2 } { \sqrt { 3 } }{/tex}
0Thank You