ABCD is a triangle DE//BC if …

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Sia ? 6 years, 6 months ago
{tex}\triangle ADE \sim \triangle ABC{/tex}
{tex}\Rightarrow \frac{ar(\triangle ADE)}{ar(\triangle ABC)}=(\frac{DE}{BC})^2{/tex}
{tex}\Rightarrow \frac{{45}}{ar(\triangle ABC)}=(\frac{6}{8})^2{/tex}
{tex}\Rightarrow \frac{{45}}{ar(\triangle ABC)}=\frac{36}{64}{/tex}
{tex}\Rightarrow ar(\triangle ABC)=\frac{64(45)}{36}{/tex}
{tex}\Rightarrow ar(\triangle ABC)=80 cm^2{/tex}
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