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In the figure AD=4cm BD=3cm CB=12cm …

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In the figure AD=4cm BD=3cm CB=12cm then find the value of cot theta

Posted by Akanksha Kamble 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

In right {tex}\triangle{/tex}ABD, {tex}\angle D = 90 ^ { \circ }{/tex}
{tex}AB^2 = AD^2 + BD^2{/tex}
{tex}\Rightarrow{/tex} {tex}AB^2 = 4^2 + 3^2{/tex}
{tex}\Rightarrow{/tex} AB = {tex}\pm 5{/tex} cm
{tex}\Rightarrow{/tex} {tex}AB = 5 cm{/tex} (Neglecting negative value)
In right {tex}\triangle{/tex}ABC , cot {tex}\theta{/tex} = {tex}\frac { \mathrm { BC } } { \mathrm { AB } } = \frac { 12 } { 5 }{/tex}

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CBSE > Class 10 > Mathematics