Draw the graphs of the following …

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Sia ? 6 years, 6 months ago
{tex}2x + 3y = 12{/tex}
{tex}x = \frac{{12 - 3y}}{2}{/tex}
When y = 0, then x = 6
When y = 2, then x = 3
We have,
{tex}x - y = 1{/tex}
{tex}x = 1 + y{/tex}
When y = 0, then x = 1
When y = -1, then x = 0
Graph of the given system is:

Clearly, the two lines intersect at {tex}A(3, 2){/tex}
We also observe that the lines meet y-axis B(0, -1) and C(0, 4)
Hence the vertices of the required triangle are {tex}A(3,2), B(0, -1)\ and\ C(0,4).{/tex}
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