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The diameter of a sphere is decreased by 25% by what percent does its surface area decrease

Posted by Sandeep Bansal 8 years, 9 months ago

CBSE > Class 09 > Mathematics

2 answers

Rashmi Bajpayee 8 years, 9 months ago

Surface area of sphere = 4πr² = πd²

New diameter = d - 25% of d = 3d/4

New Surface Area = π(3d/4)² = 9πd²/16

Decrease in Surface area = πd² - (9πd²/16) = 7πd²/16

% decrease in SA = (7πd²/16 × πd²) × 100

= 43.75%

3Thank You

Shivam Sanu 8 years, 9 months ago

43.75%

0Thank You

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